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  • Home

    [LeetCode 75] Search a 2D Matrix

    Published Jun 04, 2022 [  BinarySearch  ]

    Problem

    Write an efficient algorithm that searches for a value target in an m x n integer matrix matrix. This matrix has the following properties:

    • Integers in each row are sorted from left to right.
    • The first integer of each row is greater than the last integer of the previous row.

    Example 1:

    Input: matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 3
    Output: true
    

    Example 2:

    Input: matrix = [[1,3,5,7],[10,11,16,20],[23,30,34,60]], target = 13
    Output: false
    

    Constraints:

    • m == matrix.length
    • n == matrix[i].length
    • 1 <= m, n <= 100
    • -10^4 <= matrix[i][j], target <= 10^4

    Thoughts

    • Binary search in correct row

    TypeScript

    function searchMatrix(matrix: number[][], target: number): boolean {
        const ROWS: number = matrix.length;
        const COLS: number = matrix[0].length;
        
        for(let i = 0; i < ROWS; i++){
            let l: number = 0, r = COLS - 1;
            // in current row
            if(matrix[i][l] <= target && target <= matrix[i][r]){
                while(l <= r){
                    const mid: number = Math.floor((l + r)/2);
                    if(matrix[i][mid] === target){
                        return true
                    }
                    if(matrix[i][mid] < target){
                        l = mid + 1
                    } else {
                        r = mid - 1
                    }
                }
            } else {
                continue;
            }
        }
        
        return false;
    };
    

    Reference