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    [LeetCode 300] Longest Increasing Subsequence

    Published Jun 03, 2022 [  DynamicProgramming  ]

    Problem

    Given an integer array nums, return the length of the longest strictly increasing subsequence.

    A subsequence is a sequence that can be derived from an array by deleting some or no elements without changing the order of the remaining elements. For example, [3,6,2,7] is a subsequence of the array [0,3,1,6,2,2,7].

    Example 1:

    Input: nums = [10,9,2,5,3,7,101,18]
    Output: 4
    Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.
    

    Example 2:

    Input: nums = [0,1,0,3,2,3]
    Output: 4
    

    Example 3:

    Input: nums = [7,7,7,7,7,7,7]
    Output: 1
    

    Constraints:

    • 1 <= nums.length <= 2500
    • -10^4 <= nums[i] <= 10^4

    Follow up:

    • Can you come up with an algorithm that runs in O(n log(n)) time complexity?

    Thoughts

    • Bottom up dynamic programming

    TypeScript

    function lengthOfLIS(nums: number[]): number {
        const LIS: number[] = Array(nums.length).fill(1);
        
        // move backward
        for(let i = nums.length - 1; i >= 0; i--){
            // check all the following values
            for(let j = i + 1; j < nums.length; j++){
                // dynamic programming condition
                if(nums[i] < nums[j]){
                    LIS[i] = Math.max(LIS[i], 1 + LIS[j])
                }
            }
        }
        
        return Math.max(...LIS)
    };
    

    Reference