Published May 27, 2022
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Given an integer array nums
, return an array answer
such that answer[i]
is
equal to the product of all the elements of nums
except nums[i]
.
The product of any prefix or suffix of nums
is guaranteed to fit in a 32-bit integer.
You must write an algorithm that runs in O(n)
time and without using the division operation.
Input: nums = [1,2,3,4]
Output: [24,12,8,6]
Input: nums = [-1,1,0,-3,3]
Output: [0,0,9,0,0]
2 <= nums.length <= 10^5
nums
is guaranteed to fit in a 32-bit integer.Can you solve the problem in O(1)
extra space complexity? (The output array
does not count as extra space for space complexity analysis.)
function productExceptSelf(nums: number[]): number[] {
const res: number[] = [];
let prefix: number = 1;
for(let i = 0; i < nums.length; i++){
if(i === 0){
res[i] = 1;
} else {
prefix *= nums[i - 1]
res[i] = prefix;
}
}
let postfix: number = 1;
for(let i = nums.length - 2; i >= 0; i--){
postfix *= nums[i + 1]
res[i] *= postfix;
}
return res;
};