Published Apr 01, 2022
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Given a string s and a dictionary of strings wordDict, return true if s can be segmented into a space-separated sequence of one or more dictionary words.
Note that the same word in the dictionary may be reused multiple times in the segmentation.
Input: s = "leetcode", wordDict = ["leet","code"]
Output: true
Explanation: Return true because "leetcode" can be segmented as "leet code".
Input: s = "applepenapple", wordDict = ["apple","pen"]
Output: true
Explanation: Return true because "applepenapple" can be segmented as "apple pen apple".
Note that you are allowed to reuse a dictionary word.
Input: s = "catsandog", wordDict = ["cats","dog","sand","and","cat"]
Output: false
1 <= s.length <= 3001 <= wordDict.length <= 10001 <= wordDict[i].length <= 20s and wordDict[i] consist of only lowercase English letters.function wordBreak(s: string, wordDict: string[]): boolean {
const LEN: number = s.length;
const dp: boolean[] = new Array(LEN + 1).fill(false);
dp[LEN] = true;
for(let i = LEN - 1; i >= 0; i--){
for(const word of wordDict){
const WORD_LEN = word.length;
if((i + WORD_LEN) <= LEN && s.substring(i, i + WORD_LEN) === word){
dp[i] = dp[i + WORD_LEN];
}
if(dp[i]){
break;
}
}
}
return dp[0]
};