Published Mar 24, 2022
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Given an unsorted array of integers nums
, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n)
time.
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
0 <= nums.length <= 105
-109 <= nums[i] <= 109
function longestConsecutive(nums: number[]): number {
let result: number = 0;
const sNum: Set<number> = new Set(nums);
for(let num of nums) {
// find the start
if(!sNum.has(num - 1)){
// update the consecutive sequence count
let temp = 0;
while(sNum.has(num + temp)){
temp++;
}
result = Math.max(result, temp)
}
}
return result;
};