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    [LeetCode 70] Climbing Stairs

    Published Jan 23, 2022 [  DynamicProgramming  ]

    Problem

    You are climbing a staircase. It takes n steps to reach the top.

    Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

    Example 1:

    Input: n = 2
    Output: 2
    Explanation: There are two ways to climb to the top.
    1. 1 step + 1 step
    2. 2 steps
    

    Example 2:

    Input: n = 3
    Output: 3
    Explanation: There are three ways to climb to the top.
    1. 1 step + 1 step + 1 step
    2. 1 step + 2 steps
    3. 2 steps + 1 step
    

    Constraints:

    1 <= n <= 45
    

    TypeScript

    Top Down

    function climbStairs(n: number): number {
        // how many ways to climb to step
        const stepToCount: Map<number, number> = new Map<number, number>();
        
        const climb = (step: number): number => {
            if(step === 0 || step === 1) return 1;
            if(stepToCount.has(step)) return stepToCount.get(step)
            
            const step1: number = climb(step - 1)
            const step2: number = climb(step - 2)
            if(!stepToCount.has(step - 1)) stepToCount.set(step - 1, step1)
            if(!stepToCount.has(step - 2)) stepToCount.set(step - 2, step2)
            
            return step1 + step2
        }
        
        return climb(n)
    };
    

    Bottom Up

    function climbStairs(n: number): number {
        // store number of ways to climb nth stair
        let table: number[] = Array(n + 1).fill(0);
        // there is only 1 way to climb 0 or 1 stairs
        table[0] = 1;
        table[1] = 1;
        
        for(let i = 2; i <= n; i++) {
    	// the way to climb ith stair comes from the sum of i - 1 and i - 2 ways
            table[i] = table[i - 1] + table[i - 2];
        }
        return table[n]
    };
    

    Reference