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  • Home

    [LeetCode 38] Count and Say

    Published Dec 18, 2021 [  Recursion  ]

    Problem

    The count-and-say sequence is a sequence of digit strings defined by the recursive formula:

    • countAndSay(1) = "1"
    • countAndSay(n) is the way you would “say” the digit string from countAndSay(n-1), which is then converted into a different digit string.

    To determine how you “say” a digit string, split it into the minimal number of groups so that each group is a contiguous section all of the same character. Then for each group, say the number of characters, then say the character. To convert the saying into a digit string, replace the counts with a number and concatenate every saying.

    Given a positive integer n, return the nth term of the count-and-say sequence.

    Example 1:

    Input: n = 1
    Output: "1"
    Explanation: This is the base case.
    

    Example 2:

    Input: n = 4
    Output: "1211"
    Explanation:
    countAndSay(1) = "1"
    countAndSay(2) = say "1" = one 1 = "11"
    countAndSay(3) = say "11" = two 1's = "21"
    countAndSay(4) = say "21" = one 2 + one 1 = "12" + "11" = "1211"
    

    Constraints:

    - 1 <= n <= 30
    

    Thoughts

    • Typical recursion problem
    • List several basic cases
    • Find out recursion formula

    Typescript

    function countAndSay(n: number): string {
        // base case
        if(n === 1) {
            return '1';
        }
    
        // generate n from n - 1
        let str = countAndSay(n - 1);
        let res = ''
        let count = 1;
        let ch = str[0]
        
        for(let i = 1; i < str.length; i++){
            if(str[i] !== ch) {
                res += `${count}${ch}`
                ch = str[i]
                count = 1;
            } else {
                count++
            }
        }
        res += `${count}${ch}`
        
        return res;
    };
    

    Reference