Tags

  • AWS (7)
  • Apigee (3)
  • ArchLinux (5)
  • Array (6)
  • Backtracking (6)
  • BinarySearch (6)
  • C++ (19)
  • CI&CD (3)
  • Calculus (2)
  • DesignPattern (43)
  • DisasterRecovery (1)
  • Docker (8)
  • DynamicProgramming (20)
  • FileSystem (11)
  • Frontend (2)
  • FunctionalProgramming (1)
  • GCP (1)
  • Gentoo (6)
  • Git (15)
  • Golang (1)
  • Graph (10)
  • GraphQL (1)
  • Hardware (1)
  • Hash (1)
  • Kafka (1)
  • LinkedList (13)
  • Linux (27)
  • Lodash (2)
  • MacOS (3)
  • Makefile (1)
  • Map (5)
  • MathHistory (1)
  • MySQL (21)
  • Neovim (10)
  • Network (66)
  • Nginx (6)
  • Node.js (33)
  • OpenGL (6)
  • PriorityQueue (1)
  • ProgrammingLanguage (9)
  • Python (10)
  • RealAnalysis (20)
  • Recursion (3)
  • Redis (1)
  • RegularExpression (1)
  • Ruby (19)
  • SQLite (1)
  • Sentry (3)
  • Set (4)
  • Shell (3)
  • SoftwareEngineering (12)
  • Sorting (2)
  • Stack (4)
  • String (2)
  • SystemDesign (13)
  • Terraform (2)
  • Tree (24)
  • Trie (2)
  • TwoPointers (16)
  • TypeScript (3)
  • Ubuntu (4)
  • Home

    [LeetCode 3] Longest Substring Without Repeating Characters

    Published Oct 06, 2021 [  TwoPointers  ]

    Problem

    Given a string s, find the length of the longest substring without repeating characters.

    Example 1:

    Input: s = “abcabcbb” Output: 3 Explanation: The answer is “abc”, with the length of 3.

    Example 2:

    Input: s = “bbbbb” Output: 1 Explanation: The answer is “b”, with the length of 1.

    Example 3:

    Input: s = “pwwkew” Output: 3 Explanation: The answer is “wke”, with the length of 3. Notice that the answer must be a substring, “pwke” is a subsequence and not a substring.

    Example 4:

    Input: s = “” Output: 0

    Constraints:

    • 0 <= s.length <= 5 * 104
    • s consists of English letters, digits, symbols and spaces.

    Thoughts

    • As usual, hash can help in array problem.
    • Sliding window can help in array/string problem

    Code

    function lengthOfLongestSubstring(s: string): number {
        let res = 0;
        let valueToIndex = {};
        let leftIndex = 0;
        
        if(s.length < 2) {
            return s.length;
        }
        
        for(let rightIndex = 0; rightIndex < s.length; rightIndex++) {
            let char = s[rightIndex];
            
            if(char in valueToIndex) { 
                // if we find a duplicate, update leftIndex value
    	    // The max here deals with case "abba"
                leftIndex = Math.max(valueToIndex[char] + 1, leftIndex);
            } 
    	// we need keep updating the mapping and res
            valueToIndex[char] = rightIndex;
            res = Math.max(res, rightIndex - leftIndex + 1)
            
        }
        return res;
    };
    

    Reference